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A horizontal force pushes a 26 kg sled along a driveway for a distance of 36 m. If the coefficient of sliding friction is 0.2, what is the work done by the friction force?​

Respuesta :

Answer:1834.56 joules

Explanation:

Distance=36m

Coefficient of friction=0.2

Mass=26kg

Acceleration due to gravity=9.8m/s^2

Reaction=mass x acceleration due to gravity

Reaction=26 x 9.8

Reaction=254.8N

Coefficient of friction=frictional force ➗ reaction

0.2=frictional force ➗ 254.8

Frictional force=0.2 x 254.8

Frictional force=50.96N

work=friction force x distance

Work=50.96 x 36

Work=1834.56

Work=1834.56 joules