What is the area of a triangle with a base of 2 and StartFraction 5 Over 8 EndFraction mm and a height of 10 mm? 6 and one-fourth millimeters squared 13 and StartFraction 1 Over 8 EndFraction millimeters squared 16 and StartFraction 3 Over 8 EndFraction millimeters squared 26 and one-fourth millimeters squared

Respuesta :

Answer:

B

Step-by-step explanation:

We have a triangle with a base of [tex]2\frac{5}{8}[/tex] mm and a height of 10 mm. The area of a triangle is denoted by: [tex]A=\frac{1}{2} bh[/tex], where b is the base and h is the height. Plug these given numbers in:

[tex]A=\frac{1}{2} bh[/tex]

[tex]A=\frac{1}{2} *2\frac{5}{8}*10=5*2\frac{5}{8}=5*\frac{2*8+5}{8} =5*\frac{21}{8} =\frac{105}{8} =13\frac{1}{8}[/tex] mm squared

The answer is thus B.

Answer:

Second one:

13 and StartFraction 1 Over 8 EndFraction millimeters squared

Step-by-step explanation:

Area = ½ × base × height

½ × 2⅝ × 10

½ × 21/8 × 10

105/8 mm²

13⅛ mm²