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Manipulate the quadratic equation x² - 6 = 5x so the equation
equals 0, then factor the quadratic using the grouping method, and
find the zeros of the function.


A. X=1 and x=6
B. X=-1 and x=-6
C. X=-1 and x=6
D. X=1 and x=-6

Must show work.

Respuesta :

nehatommy04
x^2-6-5x=0
x^2-5x-6=0
x^2-6x+1x-6=0
x(x-6)+1(x-6)=0
(x-6)(x+1)=0
x-6=0
x=0+6
x=6
x+1=0
x=0-1
x=-1
Option C
altavistard

Answer:

answer B:  x = -1 and x = 6

Step-by-step explanation:

Rewrite x² - 6 = 5x as x² - 5x - 6  = 0, which is in standard form for a quadratic.

Factoring by grouping results in  x^2 - 6x + 1x - 6. pr

                                                       x(x - 6) + 1(x - 6) = 0.  

This simplifies to (x - 6)(x + 1) = 0, whose solutions are x = 6 and x = -1.

This corresponds to given answer B:  x = -1 and x = 6

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