Answer:
Problem D: x = 24; m<JMK = 96
Problem A: x = 8; m<DBC = 32
Step-by-step explanation:
Problem D.
According to the Angle Addition Postulate,
m<JML = m<JMK + m<KML
m<JML = 131
m<JMK = 4x
m<KML = x + 11
131 = 4x + x + 11
131 = 5x + 11
120 = 5x
24 = x
x = 24
m<JMK = 4x = 4(24) = 96
Problem A:
According to the Angle Addition Postulate,
m<ABC = m<ABD + m<DBC
m<ABC = 55
m<ABD = 23
m<DBC = 4x
55 = 23 + 4x
32 = 4x
8 = x
x = 8
m<DBC = 4x = 4(8) = 32
