Respuesta :
2x - 3y = 3.....multiply by 4
5x - 4y = 4....multiply by -3
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8x - 12y = 12 (result of multiplying by 4)
-15x + 12y = -12 (result of multiplying by -3)
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- 7x = 0
x = 0 <===
5x - 4y = 4....multiply by -3
--------------
8x - 12y = 12 (result of multiplying by 4)
-15x + 12y = -12 (result of multiplying by -3)
-------------
- 7x = 0
x = 0 <===
Answer:
B
Step-by-step explanation:
We need to solve for [tex]x[/tex] here.
Equation 1: [tex]2x-3y=3[/tex]
Equation 2: [tex]5x-4y=4[/tex]
Solving for [tex]y[/tex] in Equation 1 and substituting that into Equation 2 gives us:
[tex]2x-3y=3\\2x-3=3y\\\frac{2x-3}{3}=y[/tex]
Substituting this expression into Equation 2 and solving for [tex]x[/tex] gives us:
[tex]5x-4(\frac{2x-3}{3})=4\\5x-(\frac{8x-12}{3})=4\\\frac{15x-8x+12}{3}=4\\15x-8x+12=12\\7x+12=12\\7x=0\\x=0[/tex]
[tex]x=0[/tex] is the solution. Answer choice B is correct.