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Organize the following expressions from greatest to least by number of terms: x + 2xyz 3x + y + z 2x2y + x2 − 3x + 4 9x2yz

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Expressions

(a) x + 2xyz: two terms

(b) 3x + y + z: three terms

(c) 3x^2 + x^2 - 3x + 4: four terms

(d) 9x^2yz: one term

The order, from greatest to least number of terms is (c), (b), (a) and (d)
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Answer:

Step-by-step explanation:

The given expressions are:

[tex]x+2xyz[/tex], [tex]3x+y+z[/tex], [tex]2x^2y+x^2-3x+4[/tex] and [tex]9x^2yz[/tex].

We have to organize these expressions from greatest to least by number of terms.

The first expression that is [tex]x+2xyz[/tex] has two terms, second expression that is [tex]3x+y+z[/tex] has three terms, third expression that is [tex]2x^2y+x^2-3x+4[/tex] has four terms and the fourth expression that is [tex]9x^2yz[/tex] has one term, thus

Expressions from greatest to least by number of terms are:

[tex](2x^2y+x^2-3x+4) >(3x+y+z)>(x+2xyz)>(9x^2yz)[/tex]