Answer:
[tex]T=2 \pi \sqrt{\frac{L}{g} }[/tex]
Step-by-step explanation:
The period of oscilations in a pendulum is defined as
[tex]T=2 \pi \sqrt{\frac{L}{g} }[/tex]
Where [tex]L[/tex] is the length of the string and [tex]g[/tex] is gravity.
Notice that the pendulum is oscillating due to gravity in the first place. Then, that acceleration of gravity is affected by the acceleartion of the elevator, which is [tex]2g[/tex]. We know that acceleration is a vector, which means the net acceleration would be [tex]-g[/tex] of gravity and [tex]2g[/tex] of the elevator, which gives us [tex]g[/tex].
Having said that, the perior of oscaillations would be the same
[tex]T=2 \pi \sqrt{\frac{L}{g} }[/tex]
Because, the net acceleartion is also the same but in different direction.
