The graph shown below expresses a radical function that can be written in the form f(x) = a(x + k)^1/n + c. What does the graph tell you about the value of a in this function?

Answer:
The value of a is 3
Step-by-step explanation:
Given the graph which shows a radical function that can be written in the form [tex]f(x) = a(x + k)^{\frac{1}{n}} + c[/tex].
we have to tell about the value of a in this function below.
The parent function of given graph is [tex]\sqrt2[/tex]
As the given function of graph is the square root function which shows
n=2 and the vertex is (-k,c)
From the graph it is clear that (-5,2)
⇒ k=5, c=2
Now, we have to find the value of a
Now, graph passes through the point (-4,5)
Hence, put all the values in order to find the value of a
[tex]f(x) = a(x + k)^{\frac{1}{n}} + c[/tex]
⇒ [tex]5=a(-4+5)^{\frac{1}{2}}+2[/tex]
⇒ [tex]5-2=a[/tex]
⇒ a=3
The value of a is 3
Graphs can be used to represent functions
The value of a is less than 0.
The function is given as:
[tex]\mathbf{f(x)=a(x + k)^\frac{1}{n} + c}[/tex]
The parent function of f(x) is:
[tex]\mathbf{y =x^\frac{1}{2}}[/tex]
So, by comparison:
[tex]\mathbf{n =2}[/tex]
The function becomes:
[tex]\mathbf{f(x)=a(x + k)^\frac{1}{2} + c}[/tex]
Next, we identify the vertex (in this case, the vertex is the minimum point on the graph)
So, we have:
[tex]\mathbf{(k,c) = (-5,2)}[/tex]
Substitute these values in [tex]\mathbf{f(x)=a(x + k)^\frac{1}{2} + c}[/tex]
So, the function becomes
[tex]\mathbf{f(x)=a(x -5)^\frac{1}{2} + 2}[/tex]
From the graph, we have the following point;
[tex]\mathbf{(x,y) = (-4,5)}[/tex]
So, the function becomes
[tex]\mathbf{5=a(-4 -5)^\frac{1}{2} + 2}[/tex]
[tex]\mathbf{5=a(-9)^\frac{1}{2} + 2}[/tex]
Subtract 2 from both sides
[tex]\mathbf{3=a(-9)^\frac{1}{2}}[/tex]
Square both sides
[tex]\mathbf{9=a(-9)}[/tex]
Divide both sides by -9
[tex]\mathbf{-1=a}[/tex]
So, we have:
[tex]\mathbf{a = -1}[/tex]
-1 is less than 0.
Hence, the value of a is less than 0.
Read more about graphs and functions at:
https://brainly.com/question/11804653