determine the factors of 4x2 5x − 6 a(4x − 2)(x 3) b(4x − 3)(x 2) c (4x − 6)(x 1) d(4x − 1)(x 6)

4x^2 + 5x - 6 = (4x - 3) (x + 2)

You can do it by using the quadratic function to solve 4x^2 + 5x - 6 = 0; the result will be x = 3/4 and x = -2

Then you have to make (x- 3/4) = 0 and (x +2 ) = 0

When you develop x - 3/4 = 0 you get 4x -3 = 0, which means that 4x - 3 is a factor. The other factor is directly x + 2.

Answer: option b: (4x -3)(x + 2)

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shivishivangi1679 shivishivangi1679 · Answer 2 · 2022-06-06T15:29:33+02:00

The factor of the given quadratic function 4x^2 + 5x - 6 would be (4x - 3) (x + 2).

What is factorization?

Factorization is expressing a mathematical quantity in terms of multiples of smaller units of similar quantities.

For an integer, factorization is decomposition of that integer in terms of smaller integers which when multiplied with each other give back that considered number.

Those composing integers are called factors of that considered integers.

The given quadratic function

4x^2 + 5x - 6 = 0;

[tex]x = \dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a}\\\\x = \dfrac{-5/4 \pm \sqrt{25/16 - 96}}{8}[/tex]

Therefore, x = 3/4 and x = -2

Also, (x- 3/4) = 0 and (x +2 ) = 0

x - 3/4 = 0

4x -3 = 0,

4x - 3 is a factor.

The other factor is directly x + 2.

The option is B (4x -3)(x + 2).

Learn more about prime factorization here:

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