Answer:
The answer to your question is T1 = 384.7 °K
Explanation:
Data
Volume 1 = V1 = 45.7 l
Temperature 1 = T1 = ?
Volume 2 = V2 = 33.9 l
Temperature 2 = T2 = 12.4°C
To solve this problem use Charles' law
V1/T1 = V2/T2
T1 = V1T2/V2
-Convert temperature to °K
T2 = 12.4 + 273 = 285.4°K
-Substitution
T1 = (45.7 x 285.4) / 33.9
-Simplification
T1 = 13042.8 / 33.9
-Result
T1 = 384.7 °K
