Answer:
[tex]T_{final}=82C[/tex]
Explanation:
Here mass of water not given directly but volume of water is given and we already know the density of water so we will use the volume density relationship to find mass.
volume=2L
density=1kg/L
[tex]density=\frac{mass}{volume}[/tex]
[tex]mass=density\times volume[/tex]
mass=2kg=2000gram
initial temperature=298K=25C
specific heat of water (C)=4.186 joule/gram
heat energy lose or gain=[tex]mC\Delta T[/tex]
[tex]477\times 10^3 J=2000g\times 4.186J/g \times \Delta T[/tex]
[tex]\Delta T=57 C[/tex]
[tex]T_{final}-T{initial}=57[/tex]
[tex]T_{final}=82C[/tex]
