Ornithologists have determined that some species of birds tend to avoid flights over large bodies of water during daylight hours. It is believed that more energy is required to fly over water than land because air generally rises over land and falls over water during the day. A bird with these tendencies is released from an island that is 5 km from the nearest point B on a straight shoreline, flies to a point C on the shoreline, and then flies along the shoreline to its nesting area D. Assume that the bird instinctively chooses a path that will minimize its energy expenditure. Points B and D are 13 km apart.
(a) In general, if it takes 1.4 times as much energy to fly over the water as land, how far should point C be from B in order to minimize the total energy expended in returning to its nesting area?
km
(b) Let W and L denote the energy (in joules) per kilometer flown over water and land respectively. Determine the ratio W/L corresponding to the minimum energy expenditure given that the bird flies to the shore at a point x kilometers from B. (Your answer may depend only on x.)
W/L =
(c) If the ornithologists observe that birds of a certain species reach the shore at a point 9 km from B, how many times more energy does it take this species to fly over water than land?

Respuesta :

Answer:

a )  To minimize energy bird should be fly 5.1 km away from point B.

c)  it take this species 1.144 times to fly over water than land

Step-by-step explanation:

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The distance of point C from B to minimize the total energy will be 5.103km.

How to calculate the distance?

The energy function is given as:

f = 1.4✓25 + ✓x² + (13 - x)

Differentiate with respect to x and equate to 0.

f'(x) = d/dx[1.4✓25 + ✓x² + (13 - x)] = 0

1.4x/(✓25 + ✓x²) - 1 = 0

1.96x² = 25 + x²

Collect like terms

1.96x² - x² = 25

0.96x² = 25

x = 5/✓0.96

x = 5.103

Therefore, the distance will be 5.103km.

The ratio W/L corresponding to the minimum energy expenditure will be calculated thus:

Let g(x) = W/L(✓25 + ✓x²) + (13 - x)

Differentiate with respect to x

g'(x) = 0

W/L x/(✓25 + ✓x²) - 1 = 0

W/L = (✓25 + ✓x²)/x

When the ornithologists observe that birds of a certain species reach the shore at a point 9 km from B, the number of times that the energy will take will be:

= [✓25 + ✓81]/9

= (✓106)/9

= 14/9

= 1.144

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