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A plane parallel plate capacitor has plates of 10 cm2 area that are 1.0 mm apart. At an instant when charge is being accumulated on the plates at a rate of 12 nC/s, the displacement current between the plates is

Respuesta :

Chrisnando

Answer:

[tex]1.2*10^-^8A[/tex]

Explanation:

We are given:

•Area of plates, a = 10cm²

Convert to meters we have

[tex]10*10^-^4m[/tex]

•Distance btw plates, d= 1.0mm convert to meters, we have

[tex] 1.0 * 10^-^3 m = 10^-^3m[/tex]

•Rate of charge, q=12nC/s

The magnetic field between the plates and the magnetic field outside the plates of a capacitor are the same, and also the conduction and displacement current are the same.

The current of a capacitor is given by charge per unit time

Thus we have, i =12nC/s

[tex]Where 1C= 10^-^9[/tex]

C/s = A

[tex]i = 12 * 10^-^9 A[/tex]

[tex]i = 1.2 * 10^-^8 A[/tex]

The displacement current between the plates should be considered as the 1.2*10^-8 A.

Calculation of the  displacement current:

Since

Area of plates, a = 10cm²

So here we have to Convert to meters

So we have 10*10^-4m

Now the distance should be 1.0mm

So,

1.0*10^-3m = 10^-3m

And, Rate of charge, q=12nC/s

So The displacement current between the plates should be considered as the 1.2*10^-8 A.

Learn more about displacement here: https://brainly.com/question/10929377

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