(2x-2y)(2y+8)
We take the first number in the first section, and multiply that against each number in the second section.
2x*2y = 4xy
2x*8=16x
So the beginning part of our equation is 4xy + 16x. Now we need to do the second number in the first section the same way. Remember to bring the subtraction sign!!
-2y*2y = -4y^2
-2y*8 = -16y
We add this to the first result:
4xy + 16x -4y^2 -16y (A)
hope it helps!!
