Answer:
2.05 atm
Explanation:
The pressure exerted by a force is equal to the rate between the force exerted and the area over which the force is exerted:
[tex]p=\frac{F}{A}[/tex]
where
p is the pressure
F is the force
A is the area
In this problem, we have the pressure written as
[tex]p=30.0 \frac{lb}{in^2}[/tex]
First, we need to convert this into SI units (Newton over squared meters, which is Pascal).
We have:
1 lb = 4.45 N
[tex]1 in^2 = 6.45\cdot 10^{-4} m^2[/tex]
So the pressure converted into SI units is
[tex]p=30.0 \frac{ln}{in^2}\cdot \frac{4.45 N/lb}{6.45\cdot 10^{-4} m^2/in^2}=2.07\cdot 10^5 Pa[/tex]
Now we know that 1 atmosphere is equivalent to
[tex]1 atm = 1.01\cdot 10^5 Pa[/tex]
So we can convert this pressure into atmospheres:
[tex]p=\frac{2.07\cdot 10^5}{1.01\cdot 10^5}=2.05 atm[/tex]
