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A particle moves along the x-axis so that at any time t, measured in seconds, its position is given by s(t) = sin(t) - 4cos(2t), measured in feet. What is the acceleration of the particle at time t = π seconds?

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amna04352

Answer:

16 ft/s²

Step-by-step explanation:

s(t) = sin(t) - 4cos(2t)

Differentiation for v

v(t) = cos(t) + 8sin(2t)

Differentiate for a

a(t) = -sin(t) + 16cos(2t)

At t = π

a(π) = -sin(π) + 16cos(2π)

= 0 + 16

= 16

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