Answer:
B.1/28
Step-by-step explanation:
The bag contains 2 blue, 5 yellow, and 1 black tile.
The total number of tiles in the bag is
n(S)=2+5+1
n(S)=8
The number of blue tiles in the bag is
n(B)=2
The number of black tile is
n(Bk)=1
The probability of choosing a blue tiles is
[tex]P(B) = \frac{2}{8} = \frac{1}{4} [/tex]
The probability of choosing a black tile without replacing the first tile is:
[tex]P(Bk)= \frac{1}{7} [/tex]
The probability of drawing a blue tile followed by a black tile if the first tile drawn is not replaced
[tex]P(B\cap Bk) = \frac{1}{4} \times \frac{1}{7} = \frac{1}{28} [/tex]
