Given:
Angola is 10 years older than Alex.
Mark is 11 years younger than Alex.
Total of their ages = 68 years
To find:
how old is the youngest of them.
Solution:
Let x be the age of Alex.
Age of Angola = 10 years older than Alex
= x + 10
Age of Mark = 11 years younger than Alex
= x - 11
Total ages = 68
[tex]x+(x+10)+(x-11)=68[/tex]
[tex]x+x+10+x-11=68[/tex]
[tex]3x-1=68[/tex]
Add 1 on both sides.
[tex]3x-1+1=68+1[/tex]
[tex]3x=69[/tex]
[tex]$\frac{3x}{3} =\frac{69}{3}[/tex]
x = 23
Age of Alex = 23
Age of Angola = 23 + 10 = 33
Age of Mark = 23 - 11 = 12
Mark is 12 years who is the youngest of them.
