To check if a point belongs to an equation, simply substitute x and y with the given values, and see if you get something true or false.
For example, for the first point, we can plug x = -4 and y = 6 to get
[tex](-4-2)^2 + (6- 6)^2 = 4 \iff (-6)^2=4 \iff 36=4[/tex]
which is false, so the point doesn't belong to the circle. Similarly, for the second point, we have
[tex](4-2)^2 + (6- 6)^2 = 4 \iff 2^2=4 \iff 4=4[/tex]
which is true, so the point belongs to the circle.
Keep going like this with the other 2 points.
