The volume of 0.89 mo of N₂ gas at STP is 19.95 L.
The ideal gas law (PV = nRT) relates the macroscopic properties of ideal gases. An ideal gas is a gas in which the particles (a) do not attract or repel one another and (b) take up no space (have no volume).
Data obtained from the question:
Mole of N₂ = 0.89moles
Volume =?
The volume of N₂ gas at STP can be obtained by using the ideal gas equation as illustrated below:
Mole of N₂ (n) = 0.89 moles
Pressure (P) = STP = 1 atm
Temperature (T) = STP = 273
Gas constant (R) = 0.0821 atm.L/Kmol
Volume =?
PV = nRT
1 × V = 0.89 × 0.0821 × 273
V = 19.947837 L=19.95 L
Therefore, the volume of N₂ gas at STP is 19.95 L
Learn more about the ideal gas here:
https://brainly.com/question/27691721
#SPJ2
