Answer: 218.75 kPa
Explanation:
Carbon dioxide is a gas with chemical formula CO2.
Original volume of CO2 (V1) = 3.50 L
Original pressure of CO2 (P1) = 125 kPa
New pressure of CO2 (P1) = ?
New Volume of CO2 (V2) = 2.0 L
Since pressure and volume are given while temperature is constant, apply the formula for Boyle's law
P1V1 = P2V2
3.50L X 125 kPa = P1 x 2.0L
437.5 L•kPa = 2.0L•P1
Divide both sides by 2.0L
437.5 L•kPa/2.0L = 2.0L•P1/2.0L
218.75 kPa = P1
Thus, the new pressure of carbon dioxide would be 218.75 kPa
The gas exerts a pressure of 218.75 kPa if the volume was decreased to 2.0L provided that it follows the ideal gas behavior.
Given that the initial volume of the carbon dioxide gas is, V = 3.5L
the initial pressure is, P = 125 kPa
The volume was decreased to 2.0L, so the final volume be represented as, V' = 2L
Let the final pressure of the gas be, P'.
Considering the behavior of the gas to be ideal. From the ideal gas equation we get that:
PV = P'V'
125×3.5 = P'×2
P' = 218.75 kPa
So the final pressure is 218.5 kPa.
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