Respuesta :
[OH-] = 1 X 10^-6 M = 10^-6 M
pOH = -log [OH-] = -log 10^-6 = 6
and as pH + pOH = 14
so pH = 14 - pOH = 14 - 6 = 8
the answer is A hope this helps :D
pOH = -log [OH-] = -log 10^-6 = 6
and as pH + pOH = 14
so pH = 14 - pOH = 14 - 6 = 8
the answer is A hope this helps :D
pOH = - log₁₀[OH]
pOH = - log₁₀[10⁻⁶]
pOH = - (-6) = 6
But pOH + pH = 14
6 + pH = 14
pH = 14 - 6 = 8
pH = 8
Option A.
pOH = - log₁₀[10⁻⁶]
pOH = - (-6) = 6
But pOH + pH = 14
6 + pH = 14
pH = 14 - 6 = 8
pH = 8
Option A.