Respuesta :
x^2 +12x =11
x^2 +12x -11 =0
x^2 +2*6x -11 =0 add to both sides 47
x^2 +12x +36 = 47
(x+6)^2 = 47
hope this will help you
x^2 +12x -11 =0
x^2 +2*6x -11 =0 add to both sides 47
x^2 +12x +36 = 47
(x+6)^2 = 47
hope this will help you
For this case we have a polynomial of the form:
[tex] x ^ 2 + 12x = 11
[/tex]
To complete the square, we must add on both sides of the equation a term of the form:
[tex] (\frac{b}{2}) ^ 2
[/tex]
Where,
b: coefficient of the exponent term equal to 1
We have then that for this case, completing squares:
[tex] x ^ 2 + 12x + (\frac{12}{2}) ^ 2 = 11 + (\frac{12}{2}) ^ 2
[/tex]
Rewriting we have:
[tex] x ^ 2 + 12x + (6) ^ 2 = 11 + (6) ^ 2
x ^ 2 + 12x + 36 = 11 + 36
[/tex]
Answer:
The number that should be added to both sides of the equation to complete the square is:
36