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If three neutrons are produced when a neutron bombards a U- 235 atom, determine the second fission product isotope when the first fission fragment is (a) xenon-133, (b) barium-144, (c) cesium-143, (d) tellurium-137, and (e) lanthanum-146.

Respuesta :

Explanation:

235 U92 + 1n0 --> A + B + 3 1n0

when A = ;

(a) xenon-133

Mass number of B = 235 + 1 - 133 -3 = 100

Atomic number = 92 - 54 = 38

Element = Sr - Strontium

(b) barium-144

Mass number of B = 235 + 1 - 144 -3 = 89

Atomic number = 92 - 56 = 36

Element = Kr - Krypton

(c) cesium-143

Mass number of B = 235 + 1 - 143 -3 = 90

Atomic number = 92 - 55 = 37

Element = Rb - Rubidium

(d) tellurium-137

Mass number of B = 235 + 1 - 137 -3 = 96

Atomic number = 92 - 52 = 40

Element = Zr - Zirconium

(e) lanthanum-146

Mass number of B = 235 + 1 - 146 -3 = 87

Atomic number = 92 - 57 = 35

Element = Br - Bromine

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