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If the radius of curvature of the convex side is 8.00 cm, find the magnitude of the radius of curvature of the concave side such that the lens will be diverging with a focal length equal to -16.4 cm. The lens is made of glass with an index of refraction equal to 1.58.

Respuesta :

thaovtp1407

Answer:

Step-by-step explanation:

As we  know, the focal length equal to -16.4 cm

<=> [tex]\frac{1}{P(lens)}[/tex] =  -16.4

<=> P(lens) = -5/82

But the formular of The Lens Maker is:

P(lens) = (n-1) ([tex]\frac{1}{R_{1} }[/tex] - [tex]\frac{1}{R_{2} }[/tex] ) where:

  • n is the refractive index of the material used  
  • R1 is the radius of curvature of sphere 1
  • R2 is the radius of curvature of sphere 2

<=>-5/82 = (1.58-1) ([tex]\frac{1}{8}[/tex] -[tex]\frac{1}{R_{2} }[/tex] )

<=> [tex]R_{2}[/tex] = 4.345 cm

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