Step-by-step explanation:
[tex] {x}^{2} - 3x + 2 \\ = {x}^{2} - 2x - x + 2 \\ = x(x - 2) - 1(x - 2) \\ = (x - 1)(x - 2) \\ let \: (x - 1) = 0 \: \: or \: (x - 2) = 0 \\ \therefore \: x = 1 \: \: or \: \: x = 2[/tex]
Hence, 1 & 2 are the zeros of the given quadratic expression.
