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jenidiane

Answer:2x^2+x-10

Step-by-step explanation: You will want to distribute this problem.

(x-2)(2x+5)

1st

distribute the x from the first parenthesis into everything in the second parenthesis. This means, multiply x by 2x and then multiply x again by 5.

That will give you 2x^2+5x

2nd

distribute -2 from the first parenthesis into everything in the second parenthesis. Same as before, just with -2 this time.

That will give you -4x-10

3rd

Put everything together and add like terms.

2x^2+5x-4x-10 , 5x and -4x are like terms, so add them together.

=2x^2+x-10

Note: your answer should be in the appropriate order. That is, in a descending order. The highest exponent comes first and then so on.

Also: If your coefficient is 1, meaning the number in front of the x is one, then you can just leave it out and simply write x.    

AnthonyFleming

Answer:

[tex]2x^{2} +x-10[/tex]

Step-by-step explanation:

All you need to do is distribute (x-2) using the FOIL method into (2x+5)

1. FOIL stand for Front, Outer, Inner, Last

Front: (x * 2x) = [tex]2x^{2}[/tex]

Outer: (x * 5) = 5x

Now combine these two values and you get [tex]2x^{2} +5x[/tex]

Inner: (-2 * 2x) = -4x

Last: (-2 * 5) = -10

Now combines these two values to the other values we combined together,

You get: [tex]2x^{2} +5x -4x-10[/tex]

Now you simplify by combining like terms: The only like terms to combine is 5x and -4x

You get: [tex]2x^{2} +x-10[/tex] (this is your answer)

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