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A baseball player signs a contract with a starting salary of $820,000 per year and an annual increase of 5% beginning in the second year. What will the athlete’s salary be, to the nearest dollars in the sixth year?

Respuesta :

devishri1977

Answer:

Step-by-step explanation:

Salary in the sixth year

[tex]=820,000*(1+\frac{5}{100})^{6}\\\\=820000*(\frac{105}{100})^{6}\\\\=820000*(1.05)^{6}\\\\=820000*1.34\\\\=1,098,878[/tex]

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