Answer:
The initial temperature was 559.21 °C
Explanation:
Mass of Magnesium(M) =63 gm
Heat absorbed (Q) = 6689 J
Specific Heat (S) = 1.023 J/gm°C
Let, Initial Temperature = [tex]t_{1}[/tex]°C
Final Temperature ([tex]t_{2}[/tex]) = 663°C
We know that, Q = M×S( [tex]t_{2}[/tex] - [tex]t_{1}[/tex])
6689 = 63 × 1.023 × ( 663 - [tex]t_{1}[/tex])
663 - [tex]t_{1}[/tex] = 6689 ÷ ( 63 × 1.023)
[tex]t_{1}[/tex] = 663 - 103.79
= 559.21 °C
