The question says "22.50x + 95 less than or equal to 240" and I'm assuming you want us to solve for the possible values of x.
Let's try to write this as an expression before solving it.
[tex]22.50x+95 \text{ less than or equal to } 240[/tex]
Since it says "less than or equal", we're going to use the less than or equal sign: ≤
[tex]22.50x+95 \leq 240[/tex]
Now, we can solve this like a normal equation (usually this isn't the case for inequalities, though). Subtract both sides by 95
[tex]22.50x \leq 145[/tex]
Divide both sides by 22.50
[tex]x \leq \dfrac{145}{22.50}[/tex]
Simplifying this fraction gives us:
[tex]\boxed{x \leq \dfrac{58}{9}}[/tex]
In decimal form, this would be:
[tex]\boxed{x\leq6.\overline{4}}[/tex]
Both of these are the same solution to the inequality. Let me know if you need any clarifications, thanks!
~ Padoru
