Answer: Highest point from the ground that ball reaches = 5.102
Explanation:
Formula -
v² - u² = 2as
final velocity v = 0
initial velocity u = 10m/s
acceleration a = g (gravity)=9.8
distance s = 3m+x (x is the height after 3m that object reaches)
0-(10)² = 2 (-g)*(3+x)
-100 = -2g*(3=x)
(3+x)=100/2g
3+x = 100/2*9.8 = 100/19.6 = 5.102
x=5.102-3
x=2.102
So, the highest point will be
3+x = 3+2.102
=5.102m
