Answer:
2.34g of NaCl
Explanation:
HCl(aq) + NaOH(aq) --------> NaCl(aq) + H2O(l)
Number of moles of HCl= 8 × 5/1000= 0.04 moles
Number of moles of NaOH= 2.4 × 20/1000= 0.048 moles
HCl is the limiting reactant
From the balanced reaction equation, 1 mole of HCl produced 58.5g of NaCl
0.04 moles of HCl will produce 0.04 × 58.5 = 2.34g of NaCl
The number of mole of sodium chloride (NaCl) produced from the reaction is 0.04 mole
Mole = Molarity x Volume
Mole of HCl = 8 × 0.005
Mole of HCl = 0.04 mole
Mole = Molarity x Volume
Mole of NaOH = 2.4 × 0.02
Mole of NaOH = 0.048 mole
HCl + NaOH —> NaCl + H₂O
From the balanced equation above,
1 mole of HCl reacted with 1 mole of NaOH.
Therefore,
0.04 mole of HCl will also react with 0.04 mole of NaOH.
From the calculation made above, we can see that only 0.04 mole out of 0.048 mole of NaOH is required to react completely with 0.04 mole of HCl.
Therefore, HCl is the limiting reactant
HCl + NaOH —> NaCl + H₂O
From the balanced equation above,
1 mole of HCl reacted to produce 1 mole of NaCl.
Therefore,
0.04 mole of HCl will also react to produce 0.04 mole of NaCl.
Thus, 0.04 mole of NaCl was obtained from the reaction.
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