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A 7.0 kg bowling ball traveling at 2.0 m/s collides with a stationary 0.5 kg beach ball in
an elastic collision. The bowling ball leaves the collision with a velocity of 1.5 m/s
traveling in the same direction as the beach ball.
Calculate the speed of the beach ball.
A 1.0 m/s
B 2.0 m/s
C 3.5 m/s
D 7.0 m/s

Respuesta :

abustanley5

Answer:

D 7.0 m/s

Explanation:

MU+mu=MV+mv

7×2+0.5×0 =7×1.5+0.5×v

14+0=10.5+0.5v

14-10.5= 0.5v

3.5=0.5v

0.5v0.5 =3.5/0.5

v= 7m/s

The speed of the beach ball is 7.0 m/s.

What is Speed?

The rate of change of position of an object in any direction is called speed.

What is elastic collision?

Collisions in which the total kinetic energy remains constant are called elastic collision.

What is inelastic collision?

Collisions in which the total Kinetic energy is less after the collision than it was before, the collision are called inelastic.

What is law of conservation of momentum?

For two or more bodies in an isolated system acting upon each other, their total momentum remains constant unless an external force is applied. Therefore, momentum can neither be created nor destroyed.

The equation representing conservation of momentum is

[tex]MU+mu=MV+mv[/tex]

While in every collision between bodies the total momentum remains the same before and after the impact.

[tex]MU+mu=MV+mv[/tex]

[tex]7*2+0.5*0 =7*1.5+0.5*v[/tex]

[tex]v[/tex] = 7.0 m/s

To know more about Momentum here

https://brainly.com/question/4956182

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