Calculator Reference A covered water tank is in the shape of a cylinder. The tank has a 28-inch diameter and a height of 66 inches. To the nearest square inch, what is the surface area of the water tank?

Respuesta :

Answer:

[tex]7037\text{ inch}^2[/tex]

Step-by-step explanation:

We have been given that a covered water tank is in the shape of a cylinder. The tank has a 28-inch diameter and a height of 66 inches. We are asked to find the surface area of the water tank.

We will use surface area of cylinder to solve our given problem.

[tex]SA=2\pi rh+2\pi r^2[/tex]

[tex]SA=2\pi r(h+r)[/tex], where,

SA = Surface area of cylinder,

r = Radius of cylinder,

h = Height of cylinder.

Radius of the given cylinder would be half the diameter that is [tex]\frac{28}{2}=14[/tex] inches.

[tex]SA=2\pi(14\text{ inch})(66\text{ inch}+14\text{ inch})[/tex]

[tex]SA=28\pi \text{ inch}(80\text{ inch})[/tex]

[tex]SA=7037.16754404\text{ inch}^2[/tex]

Upon rounding to nearest square inch, we will get:

[tex]SA\approx 7037\text{ inch}^2[/tex]

Therefore, the surface area of the water tank is approximately 7037 square inches.