Answer:
The acceleration of m₂ is 1.6 m/s².
Explanation:
Given that,
First mass = 4.7 kg
Second mass = 6.6 kg
Here, no friction
So, [tex]T_{1}=T_{2}[/tex]
[tex]a_{1}=a_{2}=a[/tex]
We need to calculate the acceleration
Using balance equation
For first mass,
[tex]T-m_{1}g=m_{1}a[/tex]...(I)
For second mass,
[tex]m_{2}g-T=m_{2}a[/tex]...(II)
From equation (I) and second
[tex]m_{2}g-m_{1}g=(m_{1}+m_{2})a[/tex]
[tex]a=\dfrac{g(m_{2}-m_{1})}{m_{1}+m_{2}}[/tex]
Put the value into the formula
[tex]a=\dfrac{9.8(6.6-4.7)}{4.7+6.6}[/tex]
[tex]a=1.6\ m/s^2[/tex]
Hence, The acceleration of m₂ is 1.6 m/s².
The acceleration of m₂ is 1.6 m/s².
Since m1=4.7 kg and m2 = 6.6 kg,
Since there is no friction so
T_1 = T_2
a_1 = a_2 = a
Now For the first mass
T - m_1g = m_1a (1)
For the second mass,
m_2g - T = m_2a (.2)
Now
m_2g - m_1g = (m_1 + m_2)a
a = {g(m_2 - m_1)}/ {m_1+m_2}
a = \{9.8(6.6 - 4.7)}/ {4.7 + 6.6}
= 1.6 m/s^2
So by applying the above formula, The acceleration of m₂ is 1.6 m/s².
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