Answer:
hypoeutectoid
Explanation:
ferrite: pure form of iron
cementite: It is iron carbide with 93.3% iron and 6.67% carbon
hypoeutectoid: Eutectoid steel with carbon fraction less than 0.8%
hypereutectoid: Eutectoid Steel with carbon content more than 0.8%
For the mentioned iron-carbide alloy,
% of carbon in iron-carbide alloy= percentage of cementite × percentage of carbon in cementite
% of carbon in iron-carbide alloy= 0.09× 0.0667
= 0.6%
so the alloy is hypoeutectoid
