Answer:
8.33% probability that Michael will be chosen first and Susan will be chosen second.
Step-by-step explanation:
Initially, there are 4 people(Susan, John, Lisa, and Michael). The probability of Michael being chosen first is 1/4.
Now, suppose Michael was chosen.
There are 3 people(Susan, John and Lisa). The probability of Susan being chosen is 1/3.
What is the probability that Michael will be chosen first and Susan will be chosen second.
Multiplying these probabilities
[tex]p = \frac{1}{4}*\frac{1}{3} = \frac{1}{12} = 0.0833[/tex]
8.33% probability that Michael will be chosen first and Susan will be chosen second.
