Answer:
The correct option is B. 13.9 units
Therefore,
The approximate length of NP is 13.9 units.
Step-by-step explanation:
Given:
Let Points be,
point N( x₁ , y₁) ≡ ( 7 , 3)
point P( x₂ , y₂) ≡ (-6, -2)
To Find:
length(NP) = ?
Solution:
Distance Formula between two points say N and P is given as,
[tex]l(NP) = \sqrt{((x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2} )}[/tex]
Substituting the values we get
[tex]l(NP) = \sqrt{((-6-7)^{2}+(-2-3)^{2} )}[/tex]
[tex]l(NP) = \sqrt{((-13)^{2}+(-5)^{2} )}[/tex]
[tex]l(NP) = \sqrt{169+25}=\sqrt{194}=13.92\approx 13.9\ units[/tex]
Therefore,
The approximate length of NP is 13.9 units.
