Answer:
9.03×10²⁴ atoms of O are in the Al(ClO₃)₃ · 6H₂O
Explanation:
We begin from this statement:
1 mol of anything has x moles of the elements and the x moles are the supscripts for example:
1 mol of H₂O has 2 moles of H and 1 mol of O
1 mol of H₂SO₄ has 2 moles of H, 1 mol of S and 4 moles of O
Therefore, in 1 mol of Al(ClO₃)₃ · 6H₂O we may have 15 moles of O
9moles in the chlorate and 6 moles from the water.
Al(ClO₃)₃ · 6H₂O is named as Aluminum chlorate hexahydrate
To determine the number of atoms we make this rule of three:
1 mol of O has 6.02×10²³ atoms (NA)
15 moles of O must have 15 . NA / 1 = 9.03×10²⁴ atoms of O
In [tex]\bold { Al(ClO_3)_3 . 6H_2O}[/tex], there are 15 atoms of the Oxygen are present.
[tex]\bold { Al(ClO_3)_3 }[/tex], tree oxygen present inside the bracket will be multiplied by three. Hence, there are 9 atoms of Oxygen is present.
Water contains 1 oxygen atom per molecule. Here 6 molecules are present. Hence, there are 6 Oxygen present.
So, the total number of Oxygen atoms = 9+ 6 = 15
Therefore, there are 15 Oxygen atoms are present in the [tex]\bold { Al(ClO_3)_3 . 6H_2O}[/tex].
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