Answer: Thus the concentration of the sulfuric acid is 0.1201 M
Explanation:
[tex]H_2SO_4+2NaOH\rightarrow Na_2SO_4+2H_2O[/tex]
To calculate the concentration of acid, we use the equation given by neutralization reaction:
[tex]n_1M_1V_1=n_2M_2V_2[/tex]
where,
[tex]n_1,M_1\text{ and }V_1[/tex] are the n-factor, molarity and volume of acid which is [tex]H_2SO_4[/tex]
[tex]n_2,M_2\text{ and }V_2[/tex] are the n-factor, molarity and volume of base which is NaOH.
We are given:
[tex]n_1=2\\M_1=?\\V_1=10.00mL\\n_2=1\\M_2=0.1250M\\V_2=19.22mL[/tex]
Putting values in above equation, we get:
[tex]2\times M_1\times 10.00=1\times 0.1250\times 19.22\\\\M_1=0.1201M[/tex]
Thus the concentration of the sulfuric acid is 0.1201
