A 44 L cylinder containing helium gas at a pressure of 43.1 atm is used to fill a weather balloon in order to lift equipment into the stratosphere. To what maximum pressure (in atm) could a 296 L balloon be filled

Respuesta :

Answer:

The value of maximum pressure the balloon could be filled = 6.40 atmosphere.

Explanation:

When helium from the cylinder is filled inside the balloon the heat & work

transfer is zero during the process. so from the first law of thermodynamics

change in internal energy is zero.

⇒ [tex]U_{2} - U_{1}[/tex] = 0

⇒ [tex]U_{2}[/tex] = [tex]U_{1}[/tex]

[tex]T_{2}[/tex] = [tex]T_{1}[/tex] ------------- (1)

Final temperature is equal to initial temperature.

Equation (1) can be written as

[tex]P_{2}V_{2}[/tex] = [tex]P_{1}V_{1}[/tex] -------------(2)

Initial volume = 44 L

Final volume = 296 L

Initial pressure = 43.1 atmosphere

Final pressure = we have to calculate

Put all the values in Equation (2) we get,

[tex]P_{2}[/tex] × 296 = 43.1 × 44  

[tex]P_{2}[/tex] = 6.40 atmosphere

This is the value of maximum pressure the balloon could be filled.