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A 0.08 kg bullet traveling at speed hits a 16.1 kg block of wood and stays in the wood. The block with the bullet imbedded in it moves forward with a velocity of 8.1 m/s. What was the velocity (speed) of the bullet immediately before it hit the block (in m/s)

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pstnonsonjoku

Answer:

1638.225ms-1

Explanation:

Mass of block= 16.1 Kg

Mass of bullet = 0.08Kg

Initial velocity of block= 0ms-1

Initial velocity of bullet= ????

Final velocity of bullet and wood= 8.1 ms-1

From Newton's third law:

Momentum before collision= momentum after collision

MAUA + MAUB= V(MA +MB)

(0.08×UA) + (16.×0)= 8.1(0.08+16.1)

0.08UA= 131.058

UA= 1638.225ms-1

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