Solution:
Given that,
B varies inversely with C
Which means,
[tex]B \propto \frac{1}{C}\\\\B = k \times \frac{1}{C} -------- eqn\ 1[/tex]
When B is 2, C is 8
Substitute B = 2 and C = 8 in eqn 1
[tex]2 = k \times \frac{1}{8}\\\\k = 16[/tex]
Find the value of c when B is 5.
Substitute B = 5 and k = 16 in eqn 1
[tex]5 = 16 \times \frac{1}{C}\\\\C = \frac{16}{5}\\\\C = 3.2[/tex]
Thus the value of C when B is 5 is 3.2
