find the numerical lengths of the diagonals of the parallelogram below where FB=4x-2 FD=3y-1 FC=3x and FA=3y-3. solve using a system of equations via substitution or elimination methods.
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Answer:
BD = 28
AC = 24
Step-by-step explanation:
Diagonals of a parallelogram bisect each other.
4x − 2 = 3y − 1
3x = 3y − 3
Using elimination to solve the system of equations, subtract the second equation from the first.
(4x − 2) − 3x = (3y − 1) − (3y − 3)
4x − 2 − 3x = 3y − 1 − 3y + 3
x − 2 = 2
x = 4
Substitute into either equation to find y.
3(4) = 3y − 3
12 = 3y − 3
15 = 3y
y = 5
The length of BD is:
4(4) − 2 + 3(5) − 1 = 28
The length of AC is:
3(4) + 3(5) − 3 = 24