Answer:
2270 A
Explanation:
First, the number of turns in the solenoid
[tex]N=\frac {l}{d}[/tex] where l is the length and d is the diameter of a single layer. In this case, the number of turns will be
[tex]N=\frac {1.8}{0.0019}=947.3684211\approx 947[/tex]
The current, I round solenoid will be given by
[tex]I=\frac {BL}{\mu_o N}[/tex] where B is the magnetic field strength, L is the length of solenoid, [tex]\mu_o[/tex] is permeability of free space and N is the number of turns. Taking the permeability of free space as [tex]4\pi\times 10^{-7} H.m^{-1}[/tex]
[tex]I=\frac {1.5\times 1.8}{4\pi\times 10^{-7} H.m^{-1} \times 947}=2270 A[/tex]
