Answer:
It took [tex]1x10^{-3}[/tex] seconds for batman's hand to stop moving.
Explanation:
Newton' s second law is defined as:
[tex]F = ma[/tex] (1)
Where m is the mass and a is the acceleration.
But it is known that the acceleration is defined as follow by the kinematic equation that corresponds to a Uniformly Accelerated Rectilinear Motion.
[tex]a = \frac{v_{2}-v_{1}}{t}[/tex] (2)
Where [tex]v_{2}[/tex] is the final velocity and [tex]v_{1}[/tex] is the initial velocity
The initial velocity of the fist will be zero ([tex]v_{1} = 0[/tex]) since it starts from a state of rest.
Then, equation 2 can be replaced in equation 1
[tex]F = m\frac{v_{2}-v_{1}}{t}[/tex] (3)
Therefore, t can be isolated from equation 3
[tex]t = m\frac{v_{2}-v_{1}}{F}[/tex] (4)
[tex]t = (5Kg)\frac{9m/s-0m/s}{45000Kg.m/s^{2}}[/tex]
[tex]t = 1x10^{-3}s[/tex]
Hence, it took [tex]1x10^{-3}[/tex] seconds for batman's hand to stop moving.
Answer:
1 × 10^-3 s.
Explanation:
Given:
Mass = 5 kg
V = 9 m/s
Force = 45000 N
Using Newton's law,
Force = mass × acceleration
= (mass × velocity)/time
45000 = (5 × 9)/time
Time = 1 × 10^-3 s.
