Respuesta :
Answer:
60% of US households have a cat or a dog
Step-by-step explanation:
We solve this problem building the Venn's diagram of these percentage.
I am going to say that:
A is the percentage of houses which have dogs.
B is the percentage of houses which have cats.
We have that:
[tex]A = a + (A \cap B)[/tex]
In which a is the percentage of houses which have dogs but not cats and [tex]A \cap B[/tex] is the percentage of houses which have both dogs and cats.
By the same logic, we have that:
[tex]B = b + (A \cap B)[/tex]
7% of households have both cats and dogs.
This means that [tex]A \cap B = 0.07[/tex]
30% of households have cats
This means that [tex]B = 0.3[/tex]
[tex]B = b + (A \cap B)[/tex]
[tex]0.3 = b + 0.07[/tex]
[tex]b = 0.23[/tex]
37% of household have dogs
This means that [tex]A = 0.37[/tex]
[tex]A = a + (A \cap B)[/tex]
[tex]0.37 = a + 0.07[/tex]
[tex]a = 0.3[/tex]
What percentage of US households have a cat or a dog ?
[tex]A \cup B = a + b + A \cap B = 0.3 + 0.23 + 0.07 = 0.6[/tex]
60% of US households have a cat or a dog
Answer:60%
Step-by-step explanation:
House hold that have dog or cat=probability that HH have a cat or dog.
P(AuB)x100%=.6x100%=60%
