Respuesta :
Answer:
2atm
Explanation:
Data obtained from the question include:
T1 = 20°C = 20 +273 = 293K
V1 = 20.0 mL
P1 = 1atm
T2 = 20°C = 20 +273 = 293K
V2 = 10mL
P2 =?
From the above, we observed that the temperature is constant. Therefore the gas is obeying Boyle's law. The new pressure can be obtain by using P1V1 =P2V2 as shown below:
P1V1 =P2V2
1 x 20 = P2 x 10
Divide both side by 10
P2 = 20/10
P2 = 2atm
Therefore, the new pressure is 2atm.
Answer:
The new pressure is 2.0 atm
Explanation:
Step 1: Data given
Temperature = 20.0 °C = 293 K
Volume = 20.0 mL = 0.02 L
The pressure = 1.0 atm
The volume decreases to 10.0 mL = 0.01 L
The temperature stays constant at 293 K
Step 2: Calculate the new pressure
P1*V1 = P2*V2
⇒with P1 = the initial pressure = 1.0 atm
⇒with V1 = the initial volume = 0.02 L
⇒with P2 = the final pressure = TO BE DETERMINED
⇒with V2 = the final volume = 0.01 L
1*0.02 = P2 * 0.01
P2 = 0.02/0.01
P2 = 2.0 atm
The new pressure is 2.0 atm