Answer:
Team's rowing speed in still water: 11.8 miles per hour.
Speed of the current: 3.4 miles per hour.
Step-by-step explanation:
Let r represent team's rowing speed in still water and speed of current be c.
Rowing speed with current would be [tex]r+c[/tex] and rowing speed against current would be [tex]r-c[/tex].
We have been given that a rowing team rowed an average of 15.2 miles per hour with the current. We can represent this information in an equation as:
[tex]r+c=15.2...(1)[/tex]
We are also told that rowing team rowed an average of 8.4 miles per hour against the current. We can represent this information in an equation as:
[tex]r-c=8.4...(2)[/tex]
Upon adding equation (1) and (2), we will get:
[tex]r+r+c+(-c)=15.2+8.4[/tex]
[tex]r+r+c-c=15.2+8.4[/tex]
[tex]2r=23.6[/tex]
[tex]\frac{2r}{2}=\frac{23.6}{2}[/tex]
[tex]r=11.8[/tex]
Therefore, teams's rowing speed in still water was 11.8 miles per hour.
Upon substituting [tex]r=11.8[/tex] in equation (1), we will get:
[tex]11.8+c=15.2[/tex]
[tex]11.8-11.8+c=15.2-11.8[/tex]
[tex]c=3.4[/tex]
Therefore, speed of the current was 3.4 miles per hour.
