Answer:
H2 + I2 —> 2HI
Explanation:
H2 + I2 —> HI
Now, let us balance the equation. This can be achieved by doing the following:
There are 2 atoms of H on the left side of the equation and 1atom on the right side. It can be balance by putting 2 in front of HI as shown below:
H2 + I2 —> 2HI
Now the equation is balanced as there are equal numbers of atoms of the different elements present on both sides of the equation.
Answer:
H2(g) + I2(g) → 2HI(g)
Explanation:
Step 1: Data given
hydrogen gas = H2(g)
iodine gas = I2(g)
hydrogen iodide = HI(g)
Step 2: The unbalanced equation
H2(g) + I2(g) → HI(g)
Step 3: Balancing the equation
On theleft side we have 2x H (in H2), On the right side we have 1x H (in HI)
To balance the amount of H on both sides we have to multiply HI on the right by 2
By multiplying HI by 2, the amount of O on both sides is also equal. The equation is balanced.
H2(g) + I2(g) → 2HI(g)
